2+log^8=4x-1

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Solution for 2+log^8=4x-1 equation:


Simplifying
2 + log8 = 4x + -1

Reorder the terms:
2 + g8lo = -1 + 4x

Solving
2 + g8lo = -1 + 4x

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + g8lo = -1 + -2 + 4x

Combine like terms: 2 + -2 = 0
0 + g8lo = -1 + -2 + 4x
g8lo = -1 + -2 + 4x

Combine like terms: -1 + -2 = -3
g8lo = -3 + 4x

Divide each side by 'lo'.
g8 = -3l-1o-1 + 4l-1o-1x

Simplifying
g8 = -3l-1o-1 + 4l-1o-1x

Reorder the terms:
g8 + 3l-1o-1 + -4l-1o-1x = -3l-1o-1 + 3l-1o-1 + 4l-1o-1x + -4l-1o-1x

Combine like terms: -3l-1o-1 + 3l-1o-1 = 0
g8 + 3l-1o-1 + -4l-1o-1x = 0 + 4l-1o-1x + -4l-1o-1x
g8 + 3l-1o-1 + -4l-1o-1x = 4l-1o-1x + -4l-1o-1x

Combine like terms: 4l-1o-1x + -4l-1o-1x = 0
g8 + 3l-1o-1 + -4l-1o-1x = 0

The solution to this equation could not be determined.

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